問題描述：在處理一般的數(shù)據(jù)記錄中，對于數(shù)字類型的字段，在Oracle的排序中，默認把null值做為大于任何數(shù)字的類型，當(dāng)然對于varchar2類型的字段，默認也是該處理方式，但是客戶要求排序的過程中，需要把null的字段默認排在前邊（從小－－>大）。一般的order by xxxx，無法解決。問題解決：方案1：可以使用復(fù)雜的使用sql：select * from (select a.*,rownum as my_sys_rownum from (select deptid,nvl(BDZNAME,' '),nvl(VOLLEVEL,'0'),ZBRL,nvl(ZBTS, '0'),nvl(FZR,'0'),nvl(DEPTIDDES,' '),nvl(TEL,' '),nvl(RUNSTATEDES,' '),nvl(ADDRESS,' '),BDZID from V_BDZ where; rownum<2000 and ZBRL is null) aunionselect b.*,rownum+(select count(*) from (select deptid,nvl(BDZNAME,' '),nvl(VOLLEVEL,'0'),ZBRL,nvl(ZBTS, '0'),nvl(FZR,'0'),nvl(DEPTIDDES,' '),nvl(TEL,' '),nvl(RUNSTATEDES,' '),nvl(ADDRESS,' '),BDZID from V_BDZ where; rownum<2000 and ZBRL is null)) as my_sys_rownum from (select deptid,nvl(BDZNAME,' '),nvl(VOLLEVEL,'0'),ZBRL,nvl(ZBTS, '0'),nvl(FZR,'0'),nvl(DEPTIDDES,' '),nvl(TEL,' '),nvl(RUNSTATEDES,' '),nvl(ADDRESS,' '),BDZID from V_BDZ where; rownum<2000 and ZBRL is not null order by ZBRL ) b)order by my_sys_rownum desc方案2：可以利用oracle中可以對order by中對比較字段做設(shè)置的方式來實現(xiàn)： 如：; ……order by nvl( aaa,'-1')